TUGAS 4

buat file berisi:

{ ordo[55,55];
n=$1;
K=1;
L=1;
M=1;

for(a=0; a<=n+2; a++) { for(b=0; b<=n+2; b++) ordo[a,b] = 0; } a=1; b=(n+1) / 2; K-=L; for(N=1; N<=n*n;) { if(ordo[a,b]==0) { K+=L; ordo[a,b] = K; if(a==n) ordo[0,b] = K; if(b==1) ordo[a,n+1] = K; if(a==n && b==1 ) ordo[0,n+1] = K; a--; b++; N++; if(a==0&&b==n+1) continue; else { if (a==0) a=n; if(b==n+1) b=1; } } else { a+=2; b-=1; K=K-L+M; } } for(a=1; a<=n; a++) T1+=ordo[a,n+1-a]; for(a=1; a<=n*5;a++) printf(" "); printf("%5d\n\n",T1); for(a=1;a<=n+1;a++) { for(b=1; b<=n; b++) { printf("%5d", ordo[a,b]); ordo[a,n+2] += ordo[a,b]; ordo[n+1,b] += ordo[a,b]; } T2 += ordo[a,b]; if(a==n+1) ordo[a,n+2] = T2; printf("%5d\n\n",ordo[a,n+2]); } }

kemudian panggil:

echo 7 | awk -f bujursangkar.txt

Sehingga hasil yang ditampilkan adalah :

30 39 48 1 10 19 28

38 47 7 9 18 27 29

46 6 8 17 26 35 37

5 14 16 25 34 36 45

13 15 24 33 42 44 4

21 23 32 41 43 3 12

22 31 40 49 2 11 20

jumlah semuanya adalah 175